# Gamma(z) as integral of a power of log(1/t) for Re(z) greater than 0

The following formula holds: $$\Gamma(z) = \displaystyle\int_0^1 \log \left( \dfrac{1}{t} \right)^{z-1} \mathrm{d}t,$$ where $\Gamma$ denotes the gamma function and $\log$ denotes the logarithm.