Log 10(z)=log 10(e)log(z)

From specialfunctionswiki
Jump to: navigation, search

Theorem

The following formula holds: $$\log_{10}(z)=\log_{10}(e)\log(z),$$ where $\log_{10}$ denotes logarithm base a, $e$ denotes e, and $\log$ denotes logarithm.

Proof

References