# Riemann zeta as contour integral

The following formula holds: $$\zeta(z)=-\dfrac{\Gamma(1-z)}{2\pi i} \displaystyle\int_C \dfrac{(-\xi)^{z-1}}{e^{\xi}-1} \mathrm{d}\xi,$$ where $\zeta$ is Riemann zeta, $\Gamma$ is gamma, $\pi$ is pi, $i$ is the imaginary number, $e^{\xi}$ denotes the exponential, and $C$ is a contour that begins at $\infty$ on the real axis, encircles the origin once counter-clockwise (excluding $\pm 2\pi i, \pm 4\pi i, \ldots$) and returns to the starting point.