Revision history of "X/(1+x) less than log(1+x)"

Jump to: navigation, search

Diff selection: Mark the radio boxes of the revisions to compare and hit enter or the button at the bottom.
Legend: (cur) = difference with latest revision, (prev) = difference with preceding revision, m = minor edit.

  • (cur | prev) 19:49, 25 June 2017‎ Tom (talk | contribs)‎ . . (363 bytes) (+363)‎ . . (Created page with "==Theorem== The following formula holds for $x>-1$: $$\dfrac{x}{1+x} < \log(1+x),$$ where $\log$ denotes the logarithm. ==Proof== ==References== * {{BookReference|Handbo...")
Retrieved from "http://specialfunctionswiki.org/index.php/X/(1%2Bx)_less_than_log(1%2Bx)"