(b-a)2F1+a2F1(a+1)-b2F1(b+1)=0

From specialfunctionswiki
Revision as of 03:14, 16 September 2016 by Tom (talk | contribs)
Jump to: navigation, search

Theorem

The following formula holds: $$(b-1){}_2F_1(a,b;c;z)+a{}_2F_1(a+1,b;c;z)-b{}_2F_1(a,b+1;c;z)=0,$$ where ${}_2F_1$ denotes hypergeometric 2F1.

Proof

References