Difference between revisions of "(c-2a-(b-a)z)2F1+a(1-z)2F1(a+1)-(c-a)2F1(a-1)=0"
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(Created page with "==Theorem== The following formula holds: $$(c-2a-(b-a)z){}_2F_1(a,b;c;z)+a(1-z){}_2F_1(a+1,b;c;z)-(c-a){}_2F_1(a-1,b;c;z),$$ where ${}_2F_1$ denotes the hypergeometric 2F1...") |
(No difference)
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Revision as of 03:08, 16 September 2016
Theorem
The following formula holds: $$(c-2a-(b-a)z){}_2F_1(a,b;c;z)+a(1-z){}_2F_1(a+1,b;c;z)-(c-a){}_2F_1(a-1,b;c;z),$$ where ${}_2F_1$ denotes the hypergeometric 2F1.