Difference between revisions of "(c-2a-(b-a)z)2F1+a(1-z)2F1(a+1)-(c-a)2F1(a-1)=0"

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==References==
 
==References==
* {{BookReference|Higher Transcendental Functions Volume I|1953|Harry Bateman|prev=findme|next=(b-a)2F1+a2F1(a+1)-b2F1(b+1)=0}}: $\S 2.8 (31)$
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* {{BookReference|Higher Transcendental Functions Volume I|1953|Arthur Erdélyi|author2=Wilhelm Magnus|author3=Fritz Oberhettinger|author4=Francesco G. Tricomi|prev=findme|next=(b-a)2F1+a2F1(a+1)-b2F1(b+1)=0}}: $\S 2.8 (31)$
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
 
[[Category:Unproven]]
 
[[Category:Unproven]]

Latest revision as of 23:23, 3 March 2018

Theorem

The following formula holds: $$(c-2a-(b-a)z){}_2F_1(a,b;c;z)+a(1-z){}_2F_1(a+1,b;c;z)-(c-a){}_2F_1(a-1,b;c;z),$$ where ${}_2F_1$ denotes the hypergeometric 2F1.

Proof

References