Difference between revisions of "1/q-number as a q-number"
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(Created page with "==Theorem== The following formula holds: $$[a]_{\frac{1}{q}}=q^{-a+1}[a]_q,$$ where $[a]_{\frac{1}{q}}$ denotes a $q$-number. ==Proof== ==References== Catego...") |
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| + | * {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-number of a negative|next=findme}}: ($6.7$) | ||
[[Category:Theorem]] | [[Category:Theorem]] | ||
[[Category:Unproven]] | [[Category:Unproven]] | ||
Latest revision as of 08:03, 18 December 2016
Theorem
The following formula holds: $$[a]_{\frac{1}{q}}=q^{-a+1}[a]_q,$$ where $[a]_{\frac{1}{q}}$ denotes a $q$-number.
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous) ... (next): ($6.7$)
