View source for Abs(log(1+z)) less than or equal to -log(1-abs(z))

==Theorem==
The following formula holds for $|z|<1$:
$$\left| \log(1+z) \right| \leq - \log(1-|z|),$$
where $\log$ denotes the [[logarithm]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Log(x) less than or equal to n(x^(1/n)-1)|next=Log(1+z) as continued fraction}}: $4.1.38$

[[Category:Theorem]]
[[Category:Unproven]]