Abs(log(1+z)) less than or equal to -log(1-abs(z))

From specialfunctionswiki
Revision as of 19:59, 25 June 2017 by Tom (talk | contribs) (Created page with "==Theorem== The following formula holds for $|z|<1$: $$\left| \log(1+z) \right| \leq - \log(1-|z|),$$ where $\log$ denotes the logarithm. ==Proof== ==References== * {{Bo...")
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to: navigation, search

Theorem

The following formula holds for $|z|<1$: $$\left| \log(1+z) \right| \leq - \log(1-|z|),$$ where $\log$ denotes the logarithm.

Proof

References