View source for Abs(z)/4 less than abs(e^z-1) less than (7abs(z))/4 for 0 less than abs(z) less than 1

==Theorem==
The following formula holds for $0<|z|<1$:
$$\dfrac{|z|}{4} < |e^z-1| < \dfrac{7|z|}{4},$$
where $e^z$ denotes the [[exponential]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=E^(-x) less than 1-(x/2) for 0 less than x less than or equal to 1.5936|next=abs(e^z-1) less than or equal to e^(abs(z))-1 less than or equal to abs(z)e^(abs(z))}}: 4.2.38

[[Category:Theorem]]
[[Category:Unproven]]