Difference between revisions of "Antiderivative of arccosh"
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(Created page with "==Theorem== The following formula holds: $$\displaystyle\int \mathrm{arccosh}(z) \mathrm{d}z = z \mathrm{arccosh}(z)-\sqrt{z-1}\sqrt{z+1}+C,$$ where $\mathrm{arccosh}$ denotes...") |
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Latest revision as of 23:43, 11 December 2016
Theorem
The following formula holds: $$\displaystyle\int \mathrm{arccosh}(z) \mathrm{d}z = z \mathrm{arccosh}(z)-\sqrt{z-1}\sqrt{z+1}+C,$$ where $\mathrm{arccosh}$ denotes the inverse hyperbolic cosine.
