Difference between revisions of "Barnes G at z+1 in terms of Barnes G and gamma"
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(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Theorem:</strong> The following formula holds: $$G(z+1)=\Gamma(z)G(z),$$ where $G$ denotes the...") |
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| − | + | ==Theorem== | |
| − | + | The following formula holds: | |
$$G(z+1)=\Gamma(z)G(z),$$ | $$G(z+1)=\Gamma(z)G(z),$$ | ||
where $G$ denotes the [[Barnes G]] function and $\Gamma$ denotes the [[gamma]] function. | where $G$ denotes the [[Barnes G]] function and $\Gamma$ denotes the [[gamma]] function. | ||
| − | + | ||
| − | + | ==Proof== | |
| − | + | ||
| − | + | ==References== | |
| + | |||
| + | [[Category:Theorem]] | ||
| + | [[Category:Unproven]] | ||
Latest revision as of 12:52, 17 September 2016
Theorem
The following formula holds: $$G(z+1)=\Gamma(z)G(z),$$ where $G$ denotes the Barnes G function and $\Gamma$ denotes the gamma function.
