Difference between revisions of "Barnes G at z+1 in terms of Barnes G and gamma"
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− | + | ==Theorem== | |
− | + | The following formula holds: | |
$$G(z+1)=\Gamma(z)G(z),$$ | $$G(z+1)=\Gamma(z)G(z),$$ | ||
where $G$ denotes the [[Barnes G]] function and $\Gamma$ denotes the [[gamma]] function. | where $G$ denotes the [[Barnes G]] function and $\Gamma$ denotes the [[gamma]] function. | ||
− | + | ||
− | + | ==Proof== | |
− | + | ||
− | + | ==References== | |
+ | |||
+ | [[Category:Theorem]] | ||
+ | [[Category:Unproven]] |
Latest revision as of 12:52, 17 September 2016
Theorem
The following formula holds: $$G(z+1)=\Gamma(z)G(z),$$ where $G$ denotes the Barnes G function and $\Gamma$ denotes the gamma function.