Difference between revisions of "Bessel at -n-1/2 in terms of Bessel polynomial"

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<strong>[[Bessel at -n-1/2 in terms of Bessel polynomial|Theorem]]:</strong> The following formula holds:
 
<strong>[[Bessel at -n-1/2 in terms of Bessel polynomial|Theorem]]:</strong> The following formula holds:
 
$$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$
 
$$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$
where $J_{-n-\frac{1}{2}}$ denotes a [[Bessel function]] and $y_n$ denotes a [[Bessel polynomial]].
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where $J_{-n-\frac{1}{2}}$ denotes a [[Bessel J sub nu|Bessel function of the first kind]] and $y_n$ denotes a [[Bessel polynomial]].
 
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<strong>Proof:</strong> █  
 
<strong>Proof:</strong> █  
 
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Revision as of 05:59, 10 June 2015

Theorem: The following formula holds: $$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$ where $J_{-n-\frac{1}{2}}$ denotes a Bessel function of the first kind and $y_n$ denotes a Bessel polynomial.

Proof: