Difference between revisions of "Bessel at -n-1/2 in terms of Bessel polynomial"

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==Theorem==
<strong>[[Bessel at -n-1/2 in terms of Bessel polynomial|Theorem]]:</strong> The following formula holds:
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The following formula holds:
 
$$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$
 
$$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$
where $J_{-n-\frac{1}{2}}$ denotes a [[Bessel J sub nu|Bessel function of the first kind]] and $y_n$ denotes a [[Bessel polynomial]].
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where $J_{-n-\frac{1}{2}}$ denotes a [[Bessel J|Bessel function of the first kind]] and $y_n$ denotes a [[Bessel polynomial]].
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<strong>Proof:</strong> █
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==Proof==
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==References==
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 20:27, 27 June 2016

Theorem

The following formula holds: $$J_{-n-\frac{1}{2}}(r) = (2 \pi r)^{-\frac{1}{2}} \left[ i^n e^{ir} y_n \left( -\dfrac{1}{ir} \right)+ \dfrac{e^{-ir}}{i^n} y_n\left( \dfrac{1}{ir} \right) \right],$$ where $J_{-n-\frac{1}{2}}$ denotes a Bessel function of the first kind and $y_n$ denotes a Bessel polynomial.

Proof

References