Difference between revisions of "Beta in terms of gamma"

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==Theorem==
<strong>[[Beta in terms of gamma|Theorem]]:</strong> The following formula holds:  
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The following formula holds:  
 
$$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$
 
$$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$
 
where $B$ denotes the [[beta]] function and $\Gamma$ denotes the [[gamma]] function.  
 
where $B$ denotes the [[beta]] function and $\Gamma$ denotes the [[gamma]] function.  
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<strong>Proof:</strong> █
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==Proof==
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==References==
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Beta in terms of sine and cosine|next=Beta is symmetric}}: $6.2.2$
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 15:10, 6 October 2016

Theorem

The following formula holds: $$B(x,y)=\dfrac{\Gamma(x)\Gamma(y)}{\Gamma(x+y)},$$ where $B$ denotes the beta function and $\Gamma$ denotes the gamma function.

Proof

References