Difference between revisions of "Cosh is even"
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Latest revision as of 22:35, 21 October 2017
Theorem
The following formula holds: $$\cosh(-z)=\cosh(z),$$ where $\cosh$ denotes hyperbolic cosine.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.5.22$
