Difference between revisions of "Derivative of secant"
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(Created page with "<div class="toccolours mw-collapsible mw-collapsed"> <strong>Proposition:</strong> $\dfrac{d}{dx}$$\csc$$(x)=-$$\cot$$(x)...") |
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| − | + | ==Theorem== | |
| − | + | The following formula holds: | |
| − | + | $$\dfrac{\mathrm{d}}{\mathrm{d}z} \csc(z)=\cot(z),$$ | |
| − | + | where $\csc$ denotes the [[cosecant]] and $\cot$ denotes the [[cotangent]]. | |
| − | + | ||
| − | + | ==Proof== | |
| + | |||
| + | ==References== | ||
| + | |||
| + | [[Category:Theorem]] | ||
| + | [[Category:Unproven]] | ||
Revision as of 07:45, 8 June 2016
Theorem
The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \csc(z)=\cot(z),$$ where $\csc$ denotes the cosecant and $\cot$ denotes the cotangent.
