Difference between revisions of "Derivative of tangent"

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==Theorem==
<strong>[[Derivative of tangent|Proposition]]:</strong> $\dfrac{d}{dx}$[[Tangent|$\tan$]]$(x)=$[[Secant|$\sec$]]$^2(x)$
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The following formula holds:
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$$\dfrac{\mathrm{d}}{\mathrm{d}z} \tan(z) = \sec^2(z),$$
<strong>Proof:</strong> proof goes here █
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where $\tan$ denotes the [[tangent]] function and $\sec$ denotes the [[secant]] function.
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==Proof==
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From the definition,
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$$\tan(z) = \dfrac{\sin(z)}{\cos(z)},$$
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so using the [[quotient rule]], the [[derivative of sine]], the [[derivative of cosine]], the [[Pythagorean identity for sin and cos]], and the definition of [[secant]],
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$$\dfrac{\mathrm{d}}{\mathrm{d}z} \tan(z) = \dfrac{\mathrm{d}}{\mathrm{d}z} \dfrac{\sin(z)}{\cos(z)} = \dfrac{\cos^2(z) + \sin^2(z)}{\cos^2(z)} = \dfrac{1}{\cos^2(z)} = \sec^2(z),$$
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as was to be shown. $\blacksquare$
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==References==
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*{{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Derivative of cosine|next=Derivative of cosecant}}: $4.3.107$
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[[Category:Theorem]]
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[[Category:Proven]]

Latest revision as of 00:35, 26 April 2017

Theorem

The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \tan(z) = \sec^2(z),$$ where $\tan$ denotes the tangent function and $\sec$ denotes the secant function.

Proof

From the definition, $$\tan(z) = \dfrac{\sin(z)}{\cos(z)},$$ so using the quotient rule, the derivative of sine, the derivative of cosine, the Pythagorean identity for sin and cos, and the definition of secant, $$\dfrac{\mathrm{d}}{\mathrm{d}z} \tan(z) = \dfrac{\mathrm{d}}{\mathrm{d}z} \dfrac{\sin(z)}{\cos(z)} = \dfrac{\cos^2(z) + \sin^2(z)}{\cos^2(z)} = \dfrac{1}{\cos^2(z)} = \sec^2(z),$$ as was to be shown. $\blacksquare$

References