Difference between revisions of "Derivative of the logarithm"

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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=findme|next=findme}}: $4.1.46$
  
 
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Revision as of 04:57, 21 December 2017

Theorem

The following formula holds: $$\dfrac{\mathrm{d}}{\mathrm{d}z} \log(z) = \dfrac{1}{z},$$ where $\log$ denotes the logarithm.

Proof

By the definition, $$\log(z) = \displaystyle\int_1^z \dfrac{1}{z} \mathrm{d}z.$$ Using the fundamental theorem of calculus, $$\dfrac{\mathrm{d}}{\mathrm{d}z} \log(z) = \dfrac{1}{z},$$ as was to be shown.

References