Difference between revisions of "Ei(x)=-Integral from -x to infinity of e^(-t)/t dt"

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==Theorem==
 
==Theorem==
 
The following formula holds for $x>0$:
 
The following formula holds for $x>0$:
$$\mathrm{Ei}(x) = -\displaystyle\int_{-x}^{\infty} \dfrac{e^{-t}}{t} \mathrm{d}t,$$
+
$$\mathrm{Ei}(x) = \mathrm{PV} -\displaystyle\int_{-x}^{\infty} \dfrac{e^{-t}}{t} \mathrm{d}t,$$
where $\mathrm{Ei}$ denotes the [[exponential integral Ei]] and $e^{-t}$ denotes the [[exponential]].
+
where $\mathrm{Ei}$ denotes the [[exponential integral Ei]], $\mathrm{PV}$ denotes the [[Cauchy principal value]], and $e^{-t}$ denotes the [[exponential]].
  
 
==Proof==
 
==Proof==

Latest revision as of 00:48, 24 March 2018

Theorem

The following formula holds for $x>0$: $$\mathrm{Ei}(x) = \mathrm{PV} -\displaystyle\int_{-x}^{\infty} \dfrac{e^{-t}}{t} \mathrm{d}t,$$ where $\mathrm{Ei}$ denotes the exponential integral Ei, $\mathrm{PV}$ denotes the Cauchy principal value, and $e^{-t}$ denotes the exponential.

Proof

References