Difference between revisions of "Gamma"

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The gamma function is the function defined by the integral (initially for positive values of $x$) by the formula
 
The gamma function is the function defined by the integral (initially for positive values of $x$) by the formula
 
$$\Gamma(x)=\displaystyle\int_0^{\infty} x^{t-1}e^{-x} dx.$$
 
$$\Gamma(x)=\displaystyle\int_0^{\infty} x^{t-1}e^{-x} dx.$$
 +
The [[analytic continuation]] of $\Gamma$ leads to a [[meromorphic function]] with poles at the negative integers.
  
 
=Recurrence=
 
=Recurrence=

Revision as of 21:02, 7 October 2014

The gamma function is the function defined by the integral (initially for positive values of $x$) by the formula $$\Gamma(x)=\displaystyle\int_0^{\infty} x^{t-1}e^{-x} dx.$$ The analytic continuation of $\Gamma$ leads to a meromorphic function with poles at the negative integers.

Recurrence

Proposition: $\Gamma(1)=1$

Proof: Compute directly $$\begin{array}{ll} \Gamma(1) &= \displaystyle\int_0^{\infty} e^{-t}t^{1-1} dt \\ &= \displaystyle\int_0^{\infty} e^{-t} dt \\ &= \left[ -e^{-t} \right]_{-\infty}^{\infty} \\ &= 0. \end{array}$$ █

Theorem: $\Gamma(x+1)=x\Gamma(x); x>0$

Proof:

Corollary: If $x \in \mathbb{N}$, then $\Gamma(x+1)=x!$, where $x!$ denotes the factorial.

Other formulas

Proposition: The following formula holds $$\Gamma(x)=\lim_{k \rightarrow \infty} \dfrac{k!k^z}{z(z+1)\ldots(z+k)}.$$

Proof:

Proposition: The following formula holds $$\dfrac{1}{\Gamma(z)} = ze^{\gamma z} \displaystyle\prod_{k=1}^{\infty} \left( 1 + \dfrac{z}{k}\right)e^{-\frac{z}{k}},$$ where $\gamma$ is the Euler-Mascheroni constant.

Proof:

Proposition: The following formula holds $$\Gamma(x)=2\displaystyle\int_0^{\infty} e^{-t^2}t^{2x-1}dt.$$

Proof:

Proposition: The following formula holds $$\displaystyle\int_0^{\frac{\pi}{2}} \cos^{2x-1}(\theta)\sin^{2y-1}(\theta) d\theta = \dfrac{\Gamma(x)\Gamma(y)}{2\Gamma(x+y)}.$$

Proof:

$\Gamma(z)$ at half integers

Proposition: $\Gamma \left( \dfrac{1}{2} \right) = \sqrt{\pi}$.

Proof:

Corollary: $\displaystyle\int_0^{\infty} e^{-t^2} dt = \dfrac{1}{2}\sqrt{\pi}$.

Other properties

Theorem (Legendre Duplication Formula): $$\Gamma(2x)=\dfrac{2^{2x-1}}{\sqrt{\pi}} \Gamma(x)\Gamma \left( x +\dfrac{1}{2} \right).$$

Proof:

Proposition: If $z=0,-1,-2,\ldots$ then $\Gamma(z)=\infty$.

Proof: proof goes here █

Theorem: The following relationship between $\Gamma$ and the $\sin$ function holds: $$\Gamma(x)\Gamma(1-x) = \dfrac{\pi}{\sin(\pi x)}.$$

Proof: proof goes here █

Proposition: $\Gamma(x) = \displaystyle\lim_{n \rightarrow \infty} \dfrac{n^x n!}{x(x+1)\ldots(x_n)}$

Proof: proof goes here █

Proposition: $\Gamma(x)\Gamma(1-x)=\dfrac{\pi}{\sin(\pi x)}$

Proof: proof goes here █

Bohr-Mollerup Theorem: The gamma function is the unique function $f$ such that

Proof: proof goes here █

References

The Gamma Function by Emil Artin