Difference between revisions of "Gamma(z)Gamma(1-z)=pi/sin(pi z)"

From specialfunctionswiki
Jump to: navigation, search
 
(No difference)

Latest revision as of 11:54, 5 April 2018

Theorem

The following formula holds: $$\Gamma(z)\Gamma(1-z) = \dfrac{\pi}{\sin(\pi z)},$$ where $\Gamma$ denotes the gamma function and $\sin$ denotes the sine function.

Proof

References