Difference between revisions of "H (nu)(x) geq 0 for x gt 0 and nu geq 1/2"

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(Created page with "==Theorem== The following formula holds for $x>0$ and $\nu \geq \dfrac{1}{2}$: $$\mathbf{H}_{\nu}(x) \geq 0,$$ where $\mathbf{H}$ denotes a Struve function. ==Proof== ==...")
 
 
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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=D/dz(z^(-nu)H (nu))=1/(sqrt(pi)2^(nu)Gamma(nu+3/2))-z^(-nu)H (nu+1)|next=}}: $12.1.14$
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=D/dz(z^(-nu)H (nu))=1/(sqrt(pi)2^(nu)Gamma(nu+3/2))-z^(-nu)H (nu+1)|next=H_(-(n+1/2))(z)=(-1)^n J_(n+1/2)(z) for integer n geq 0}}: $12.1.14$
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
 
[[Category:Unproven]]
 
[[Category:Unproven]]

Latest revision as of 00:57, 21 December 2017

Theorem

The following formula holds for $x>0$ and $\nu \geq \dfrac{1}{2}$: $$\mathbf{H}_{\nu}(x) \geq 0,$$ where $\mathbf{H}$ denotes a Struve function.

Proof

References