Difference between revisions of "H (nu)(x) geq 0 for x gt 0 and nu geq 1/2"
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Revision as of 00:56, 21 December 2017
Theorem
The following formula holds for $x>0$ and $\nu \geq \dfrac{1}{2}$: $$\mathbf{H}_{\nu}(x) \geq 0,$$ where $\mathbf{H}$ denotes a Struve function.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous): $12.1.14$
