Difference between revisions of "Hadamard gamma"

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The Hadamard gamma function is defined by the formula
 
The Hadamard gamma function is defined by the formula
$$H(x)=\dfrac{1}{\Gamma(1-x)} \dfrac{d}{dx} \log \left( \dfrac{\Gamma(\frac{1}{2}-\frac{x}{2})}{\Gamma(1-\frac{x}{2})} \right),$$
+
$$H(x)=\dfrac{1}{\Gamma(1-x)} \dfrac{\mathrm{d}}{\mathrm{d}x} \log \left( \dfrac{\Gamma(\frac{1}{2}-\frac{x}{2})}{\Gamma(1-\frac{x}{2})} \right),$$
 
where $\Gamma$ denotes the [[gamma function]].
 
where $\Gamma$ denotes the [[gamma function]].
 
=Properties=
 
=Properties=
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<div class="toccolours mw-collapsible mw-collapsed">
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<strong>Theorem:</strong> The function $H$ is an [[entire function]].
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<div class="mw-collapsible-content">
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<strong>Proof:</strong> proof goes here █
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</div>
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</div>
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<div class="toccolours mw-collapsible mw-collapsed">
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<strong>Theorem:</strong> The function $H$ satisfies the formula
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$$H(x+1)=xH(x)+\dfrac{1}{\Gamma(1-x)}.$$
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<div class="mw-collapsible-content">
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<strong>Proof:</strong> proof goes here █
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</div>
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</div>
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<div class="toccolours mw-collapsible mw-collapsed">
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<strong>Theorem:</strong> Define $\alpha_0 \approx 1.5031\ldots$ to be the only solution of the equation $H(2t)=2H(t)$. Then the inequality $H(x)+H(y) \leq H(x+y)$ holds for all real numbers $x,y$ with $x,y \geq \alpha$ if and only if $\alpha \geq \alpha_0$.
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<div class="mw-collapsible-content">
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<strong>Proof:</strong> proof goes here █
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</div>
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</div>
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=See Also=
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[[Gamma]]
  
 
=References=
 
=References=
[http://www.luschny.de/math/factorial/hadamard/HadamardsGammaFunctionMJ.html Is the Gamma function misdefined?]
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[http://www.luschny.de/math/factorial/hadamard/HadamardsGammaFunctionMJ.html Is the Gamma function misdefined?]<br />
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[http://www.jstor.org/discover/10.2307/2309786?sid=21105065140641&uid=3739256&uid=2129&uid=70&uid=3739744&uid=4&uid=2 Leonhard Euler's Integral: A Historical Profile of the Gamma Function]<br />
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[http://link.springer.com/article/10.1007%2Fs12188-008-0009-5 A superadditive property of Hadamard's gamma function]<br />
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[[Category:SpecialFunction]]

Latest revision as of 18:28, 24 May 2016

The Hadamard gamma function is defined by the formula $$H(x)=\dfrac{1}{\Gamma(1-x)} \dfrac{\mathrm{d}}{\mathrm{d}x} \log \left( \dfrac{\Gamma(\frac{1}{2}-\frac{x}{2})}{\Gamma(1-\frac{x}{2})} \right),$$ where $\Gamma$ denotes the gamma function.

Properties

Theorem: We can write $$H(x)=\dfrac{\psi(1-\frac{x}{2})-\psi(\frac{1}{2}-\frac{x}{2})}{2\Gamma(1-x)},$$ where $\psi$ is the digamma function.

Proof: proof goes here █

Theorem: The function $H$ is an entire function.

Proof: proof goes here █

Theorem: The function $H$ satisfies the formula $$H(x+1)=xH(x)+\dfrac{1}{\Gamma(1-x)}.$$

Proof: proof goes here █

Theorem: Define $\alpha_0 \approx 1.5031\ldots$ to be the only solution of the equation $H(2t)=2H(t)$. Then the inequality $H(x)+H(y) \leq H(x+y)$ holds for all real numbers $x,y$ with $x,y \geq \alpha$ if and only if $\alpha \geq \alpha_0$.

Proof: proof goes here █

See Also

Gamma

References

Is the Gamma function misdefined?
Leonhard Euler's Integral: A Historical Profile of the Gamma Function
A superadditive property of Hadamard's gamma function