View source for Limit of erf when z approaches infinity and the modulus of arg(z) is less than pi/4

==Theorem==
The following formula holds for $\left|\mathrm{arg}(z)\right| < \dfrac{\pi}{4}$ where $\mathrm{arg}(z)$ denotes the [[argument]] of $z$:
$$\displaystyle\lim_{z \rightarrow \infty} \mathrm{erf}(z)=1,$$
where $\mathrm{erf}$ denotes the [[error function]].
==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Continued fraction for 1/sqrt(pi) integral from -infinity to infinity of e^(-t^2)/(z-t) dt|next=findme}}: 7.1.16

[[Category:Theorem]]