Difference between revisions of "Logarithm (multivalued) of a quotient is a difference of logarithms (multivalued)"

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(Created page with "==Theorem== Let $z_1,z_2 \in \mathbb{C}$ with $z_2 \neq 0$. The following formula holds: $$\mathrm{Log} \left( \dfrac{z_1}{z_2} \right) \subset \mathrm{Log}(z_1) - \mathrm{Log...")
 
 
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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Logarithm of product is a sum of logarithms|next=Logarithm of a quotient is a difference of logarithms}}: 4.1.8
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Logarithm of product is a sum of logarithms|next=Logarithm of a quotient is a difference of logarithms}}: $4.1.8$
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 17:26, 27 June 2016

Theorem

Let $z_1,z_2 \in \mathbb{C}$ with $z_2 \neq 0$. The following formula holds: $$\mathrm{Log} \left( \dfrac{z_1}{z_2} \right) \subset \mathrm{Log}(z_1) - \mathrm{Log}(z_2),$$ where $\mathrm{Log}$ denotes the logarithm (multivalued) and $\mathrm{Log}(z_1) - \mathrm{Log}(z_2)$ denotes the difference set of $\mathrm{Log}(z_1)$ and $\mathrm{Log}(z_2)$.

Proof

References