Difference between revisions of "Logarithm (multivalued) of product is a sum of logarithms (multivalued)"

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(Created page with "==Theorem== The following formula holds for any $z_1,z_2 \in \mathbb{C}$: $$\mathrm{Log}\left( z_1z_2 \right) \subset \mathrm{Log}(z_1) + \mathrm{Log}(z_2),$$ where $\mathrm{L...")
 
 
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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Relationship between logarithm (multivalued) and logarithm|next=Logarithm of product is a sum of logarithms}}: 4.1.6
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Relationship between logarithm (multivalued) and logarithm|next=Logarithm of product is a sum of logarithms}}: $4.1.6$
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 17:24, 27 June 2016

Theorem

The following formula holds for any $z_1,z_2 \in \mathbb{C}$: $$\mathrm{Log}\left( z_1z_2 \right) \subset \mathrm{Log}(z_1) + \mathrm{Log}(z_2),$$ where $\mathrm{Log}$ denotes the logarithm (multivalued) and $\mathrm{Log}(z_1) + \mathrm{Log}(z_2)$ denotes the sumset of $\mathrm{Log}(z_1)$ and $\mathrm{Log}(z_2)$.

Proof

References