Difference between revisions of "Logarithm of product is a sum of logarithms"
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+ | ==Theorem== | ||
+ | Let $z_1,z_2 \in \mathbb{C}$ such that $-\pi < \mathrm{arg}(z_1) + \mathrm{arg}(z_2) \leq \pi$. Then the following formula holds: | ||
+ | $$\log(z_1z_2) = \log(z_1)+\log(z_2),$$ | ||
+ | where $\log$ denotes the [[logarithm]]. | ||
+ | |||
+ | ==Proof== | ||
+ | |||
==References== | ==References== | ||
− | * {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Logarithm (multivalued) of product is a sum of logarithms (multivalued)|next=}}: 4.1.7 | + | * {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Logarithm (multivalued) of product is a sum of logarithms (multivalued)|next=Logarithm (multivalued) of a quotient is a difference of logarithms (multivalued)}}: $4.1.7$ |
+ | |||
+ | [[Category:Theorem]] | ||
+ | [[Category:Unproven]] |
Latest revision as of 17:25, 27 June 2016
Theorem
Let $z_1,z_2 \in \mathbb{C}$ such that $-\pi < \mathrm{arg}(z_1) + \mathrm{arg}(z_2) \leq \pi$. Then the following formula holds: $$\log(z_1z_2) = \log(z_1)+\log(z_2),$$ where $\log$ denotes the logarithm.
Proof
References
- 1964: Milton Abramowitz and Irene A. Stegun: Handbook of mathematical functions ... (previous) ... (next): $4.1.7$