Difference between revisions of "Logarithmic derivative of Jacobi theta 1 equals cotangent + a sum of sines"

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==Theorem==
 
==Theorem==
 
The following formula holds:
 
The following formula holds:
$$\dfrac{\vartheta_1'(u,q)}{\vartheta_1(u,q)} = \cot(u)+4\displaystyle\sum_{k=1}^{\infty} \dfrac{q^{2n}}{1-q^{2n}} \sin(2nu),$$
+
$$\dfrac{\vartheta_1'(u,q)}{\vartheta_1(u,q)} = \cot(u)+4\displaystyle\sum_{k=1}^{\infty} \dfrac{q^{2k}}{1-q^{2k}} \sin(2ku),$$
 
where $\vartheta_1$ denots the [[Jacobi theta 1]], $\cot$ denotes [[cotangent]], and $\sin$ denotes [[sine]].
 
where $\vartheta_1$ denots the [[Jacobi theta 1]], $\cot$ denotes [[cotangent]], and $\sin$ denotes [[sine]].
  

Revision as of 07:14, 27 June 2016

Theorem

The following formula holds: $$\dfrac{\vartheta_1'(u,q)}{\vartheta_1(u,q)} = \cot(u)+4\displaystyle\sum_{k=1}^{\infty} \dfrac{q^{2k}}{1-q^{2k}} \sin(2ku),$$ where $\vartheta_1$ denots the Jacobi theta 1, $\cot$ denotes cotangent, and $\sin$ denotes sine.

Proof

References