View source for NC n^(lambda)(x)=(n-1+2lambda)xC (n-1)^(lambda)(x)-2lambda(1-x^2)C (n-2)^(lambda-1)(x)

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==Theorem==
The following formula holds:
$$nC_n^{\lambda}(x) = (n-1+2\lambda)xC_{n-1}^{\lambda}(x) - 2\lambda(1-x^2)C_{n-2}^{\lambda-1}(x),$$
where $C_n^{\lambda}$ denotes [[Gegenbauer C]].

==Proof==

==References==

[[Category:Theorem]]
[[Category:Unproven]]

Return to NC n^(lambda)(x)=(n-1+2lambda)xC (n-1)^(lambda)(x)-2lambda(1-x^2)C (n-2)^(lambda-1)(x).

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