Difference between revisions of "NC n^(lambda)(x)=2lambda(xC (n-1)^(lambda+1)(x)-C (n-2)^(lambda+1)(x))"
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(Created page with "==Theorem== The following formula holds: $$nC_n^{\lambda}(x) = 2\lambda(xC_{n-1}^{\lambda+1}(x) - C_{n-2}^{\lambda+1}(x)),$$ where $C_n^{\lambda}$ denotes Gegenbauer C. =...") |
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Revision as of 23:48, 19 December 2017
Theorem
The following formula holds: $$nC_n^{\lambda}(x) = 2\lambda(xC_{n-1}^{\lambda+1}(x) - C_{n-2}^{\lambda+1}(x)),$$ where $C_n^{\lambda}$ denotes Gegenbauer C.
