Difference between revisions of "Paper folding constant"
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(Created page with "The paper folding constant $P$ is given by $$P=\displaystyle\sum_{k=0}^{\infty} \dfrac{1}{2^{2^k}} \left( 1 - \dfrac{1}{2^{2^{k+2}}} \right)^{-1}.$$") |
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Revision as of 18:10, 14 May 2016
The paper folding constant $P$ is given by $$P=\displaystyle\sum_{k=0}^{\infty} \dfrac{1}{2^{2^k}} \left( 1 - \dfrac{1}{2^{2^{k+2}}} \right)^{-1}.$$
