Difference between revisions of "Product rule for derivatives"

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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Sum rule for derivatives|next=}}: 3.3.3
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Sum rule for derivatives|next=Quotient rule for derivatives}}: $3.3.3$

Latest revision as of 17:21, 27 June 2016

Theorem

Let $f$ and $g$ be differentiable functions. Then, $$\dfrac{\mathrm{d}}{\mathrm{d}x} \left[ f(x)g(x) \right] = f'(x)g(x) + f(x)g'(x),$$ where $\dfrac{\mathrm{d}}{\mathrm{d}x}$ denotes the derivative operator.

Proof

References