Difference between revisions of "Q-derivative of q-Sine"

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The following formula holds:
 
The following formula holds:
 
$$D_q \mathrm{Sin}_q(bz) = b \mathrm{Cos}_q(bz),$$
 
$$D_q \mathrm{Sin}_q(bz) = b \mathrm{Cos}_q(bz),$$
where $D_q$ is the [[q-difference operator]], $\mathrm{Sin}_q$ is the [[Q-Sin|$q$-Sine function]], and $\mathrm{Cos}_q$ is the [[Q-Cos|$q$-cosine function]].
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where $D_q$ is the [[q-derivative]], $\mathrm{Sin}_q$ is the [[Q-Sin|$q$-Sine function]], and $\mathrm{Cos}_q$ is the [[Q-Cos|$q$-cosine function]].
  
 
==Proof==
 
==Proof==
  
 
==References==
 
==References==
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* {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-Cos|next=q-derivative of q-Cosine}}: (6.170)
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
 
[[Category:Unproven]]
 
[[Category:Unproven]]

Latest revision as of 23:27, 26 June 2016

Theorem

The following formula holds: $$D_q \mathrm{Sin}_q(bz) = b \mathrm{Cos}_q(bz),$$ where $D_q$ is the q-derivative, $\mathrm{Sin}_q$ is the $q$-Sine function, and $\mathrm{Cos}_q$ is the $q$-cosine function.

Proof

References