Difference between revisions of "Q-difference equation for q-exponential E sub 1/q"
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(Created page with "==Theorem== The following formula holds: $$D_q E_{\frac{1}{q}}(az)=aE_{\frac{1}{q}}(qaz),$$ where $D_q$ denotes the q-difference operator and $E_{\frac{1}{q}}$ denotes the...") |
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==References== | ==References== | ||
| − | * {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-exponential E sub 1/q|next= | + | * {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-exponential E sub 1/q|next=Product representation of q-exponential E sub 1/q}}: ($6.154$) |
[[Category:Theorem]] | [[Category:Theorem]] | ||
[[Category:Unproven]] | [[Category:Unproven]] | ||
Latest revision as of 07:41, 18 December 2016
Theorem
The following formula holds: $$D_q E_{\frac{1}{q}}(az)=aE_{\frac{1}{q}}(qaz),$$ where $D_q$ denotes the q-difference operator and $E_{\frac{1}{q}}$ denotes the $q$-exponential $E_{\frac{1}{q}}$.
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous) ... (next): ($6.154$)
