Difference between revisions of "Q-difference equation for q-exponential E sub 1/q"
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Revision as of 22:49, 16 June 2016
Theorem
The following formula holds: $$D_q E_{\frac{1}{q}}(az)=aE_{\frac{1}{q}}(qaz),$$ where $D_q$ denotes the q-difference operator and $E_{\frac{1}{q}}$ denotes the $q$-exponential $E_{\frac{1}{q}}$.
Proof
References
- 2012: Thomas Ernst: A Comprehensive Treatment of q-Calculus ... (previous) ... (next): (6.154)
