Difference between revisions of "Q-number"

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m (Tom moved page Q-numbers to Q-number)
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Let $q \neq 0$ and define the $q$ numbers
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Let $q \in \mathbb{C} \setminus \{1\}$ and define the $q$ numbers
 
$$[n]_q=\dfrac{1-q^n}{1-q}=1+q+q^2+\ldots+q^{n-1}.$$
 
$$[n]_q=\dfrac{1-q^n}{1-q}=1+q+q^2+\ldots+q^{n-1}.$$

Revision as of 04:46, 26 August 2015

Let $q \in \mathbb{C} \setminus \{1\}$ and define the $q$ numbers $$[n]_q=\dfrac{1-q^n}{1-q}=1+q+q^2+\ldots+q^{n-1}.$$