Difference between revisions of "Q-number when a=n is a natural number"

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==Theorem==
 
==Theorem==
 
The following formula holds for $n \in \{1,2,\ldots\}$ and $q \in \mathbb{C} \setminus \{0,1\}$:
 
The following formula holds for $n \in \{1,2,\ldots\}$ and $q \in \mathbb{C} \setminus \{0,1\}$:
$$[n]_q=\displaystyle\sum_{k=1}^n q^{k-1}.$$  
+
$$[n]_q=\displaystyle\sum_{k=1}^n q^{k-1},$$
 +
where $[n]_q$ denotes a [[q-number|$q$-number]].
  
 
==Proof==
 
==Proof==
  
 
==References==
 
==References==
* {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-number|next=q-factorial}}: (6.2)
+
* {{BookReference|A Comprehensive Treatment of q-Calculus|2012|Thomas Ernst|prev=q-number|next=q-factorial}}: ($6.2$)
  
 
[[Category:Theorem]]
 
[[Category:Theorem]]
 
[[Category:Unproven]]
 
[[Category:Unproven]]

Latest revision as of 20:17, 18 December 2016

Theorem

The following formula holds for $n \in \{1,2,\ldots\}$ and $q \in \mathbb{C} \setminus \{0,1\}$: $$[n]_q=\displaystyle\sum_{k=1}^n q^{k-1},$$ where $[n]_q$ denotes a $q$-number.

Proof

References