Difference between revisions of "Relationship between Bessel I sub -1/2 and cosh"

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==Theorem==
<strong>[[Relationship between Bessel I sub 1/2 and cosh|Proposition]]:</strong> The following formula holds:
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The following formula holds:
 
$$I_{-\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}} \cosh(z),$$
 
$$I_{-\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}} \cosh(z),$$
 
where $I_{-\frac{1}{2}}$ denotes [[Modified Bessel I sub nu|the modified Bessel function of the first kind]] and $\cosh$ denotes the [[Cosh|hyperbolic cosine]].
 
where $I_{-\frac{1}{2}}$ denotes [[Modified Bessel I sub nu|the modified Bessel function of the first kind]] and $\cosh$ denotes the [[Cosh|hyperbolic cosine]].
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<strong>Proof:</strong> █
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==Proof==
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==References==
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 00:01, 17 June 2016

Theorem

The following formula holds: $$I_{-\frac{1}{2}}(z)=\sqrt{\dfrac{2}{\pi z}} \cosh(z),$$ where $I_{-\frac{1}{2}}$ denotes the modified Bessel function of the first kind and $\cosh$ denotes the hyperbolic cosine.

Proof

References