Difference between revisions of "Relationship between coth, inverse Gudermannian, and csc"

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==Theorem==
<strong>[[Relationship between coth, inverse Gudermannian, and csc|Theorem]]:</strong> The following formula holds:
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The following formula holds:
 
$$\mathrm{coth}(\mathrm{gd}^{-1}(x))=\csc(x),$$
 
$$\mathrm{coth}(\mathrm{gd}^{-1}(x))=\csc(x),$$
 
where $\mathrm{coth}$ is the [[coth|hyperbolic cotangent]], $\mathrm{gd}^{-1}$ is the [[inverse Gudermannian]], and $\csc$ is the [[cosecant]].
 
where $\mathrm{coth}$ is the [[coth|hyperbolic cotangent]], $\mathrm{gd}^{-1}$ is the [[inverse Gudermannian]], and $\csc$ is the [[cosecant]].
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<strong>Proof:</strong> █
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==Proof==
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==References==

Revision as of 04:37, 6 June 2016

Theorem

The following formula holds: $$\mathrm{coth}(\mathrm{gd}^{-1}(x))=\csc(x),$$ where $\mathrm{coth}$ is the hyperbolic cotangent, $\mathrm{gd}^{-1}$ is the inverse Gudermannian, and $\csc$ is the cosecant.

Proof

References