Relationship between coth and csch

From specialfunctionswiki
Revision as of 03:54, 17 June 2016 by Tom (talk | contribs)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to: navigation, search

Theorem

The following formula holds: $$\mathrm{coth} \left( \dfrac{z}{2} \right) - \mathrm{coth}(z) = \mathrm{csch}(z),$$ where $\mathrm{coth}$ denotes the hyperbolic cotangent and $\mathrm{csch}$ denotes the hyperbolic cosecant.

Proof

References