Difference between revisions of "Relationship between csc, Gudermannian, and coth"

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==Theorem==
<strong>[[Relationship between csc, Gudermannian, and coth|Theorem]]:</strong> The following formula holds:
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The following formula holds:
 
$$\csc(\mathrm{gd}(x))=\mathrm{coth}(x),$$
 
$$\csc(\mathrm{gd}(x))=\mathrm{coth}(x),$$
 
where $\csc$ is the [[cosecant]], $\mathrm{gd}$ is the [[Gudermannian]], and $\mathrm{coth}$ is the [[coth|hyperbolic cotangent]].
 
where $\csc$ is the [[cosecant]], $\mathrm{gd}$ is the [[Gudermannian]], and $\mathrm{coth}$ is the [[coth|hyperbolic cotangent]].
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<strong>Proof:</strong> █
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==Proof==
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==References==

Revision as of 04:36, 6 June 2016

Theorem

The following formula holds: $$\csc(\mathrm{gd}(x))=\mathrm{coth}(x),$$ where $\csc$ is the cosecant, $\mathrm{gd}$ is the Gudermannian, and $\mathrm{coth}$ is the hyperbolic cotangent.

Proof

References