Difference between revisions of "Relationship between sech, inverse Gudermannian, and cos"
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Revision as of 23:36, 25 August 2015
Theorem: The following formula holds: $$\mathrm{sech}(\mathrm{gd}^{-1}(x))=\cos(x),$$ where $\mathrm{sech}$ is the hyperbolic secant, $\mathrm{gd}^{-1}$ is the inverse Gudermannian, and $\cos$ is the cosine.
Proof: █