View source for Series for log(z) for absolute value of (z-1) less than 1

==Theorem==
The following formula holds for $|z-1| \leq 1$ and $z \neq 0$:
$$\log(z) = -\displaystyle\sum_{k=1}^{\infty} \dfrac{(-1)^k(z-1)^k}{k},$$
where $\log(z)$ denotes the [[logarithm]].
==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Series for log(z) for Re(z) greater than 1/2|next=Series for log(z) for Re(z) greater than 0}}: $4.1.26$

[[Category:Theorem]]
[[Category:Unproven]]