Difference between revisions of "Series for log(z) for absolute value of (z-1) less than 1"

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==References==
 
==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Series for log(z) for Re(z) greater than 1/2|next=Series for log(z) for Re(z) greater than 0}}: 4.1.26
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* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Series for log(z) for Re(z) greater than 1/2|next=Series for log(z) for Re(z) greater than 0}}: $4.1.26$
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[[Category:Theorem]]
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[[Category:Unproven]]

Latest revision as of 17:28, 27 June 2016

Theorem

The following formula holds for $|z-1| \leq 1$ and $z \neq 0$: $$\log(z) = -\displaystyle\sum_{k=1}^{\infty} \dfrac{(-1)^k(z-1)^k}{k},$$ where $\log(z)$ denotes the logarithm.

Proof

References