Difference between revisions of "Square of i"
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Latest revision as of 03:34, 8 December 2016
Theorem
The following formula holds: $$i^2=-1,$$ where $i$ denotes the imaginary number.
Proof
From the definition of $i$, $$i=\sqrt{-1}.$$ Squaring both sides shows $$i^2 = \left( \sqrt{-1} \right)^2 = -1,$$ as was to be shown.
