View source for Sum of sum of divisors function equals product of Riemann zeta for Re(z) greater than k+1

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==Theorem==
The following formula holds for $\mathrm{Re}(z)>k+1$:
$$\displaystyle\sum_{k=1}^{\infty} \dfrac{\sigma_n(k)}{k^z} = \zeta(z) \zeta(z-n),$$
where $\sigma_n$ denotes the [[sum of divisors]] function and $\zeta$ denotes the [[Riemann zeta]].

==Proof==

==References==
* {{BookReference|Handbook of mathematical functions|1964|Milton Abramowitz|author2=Irene A. Stegun|prev=Sum of divisors|next=findme}}: $24.3.3 I.B.$

[[Category:Theorem]]
[[Category:Unproven]]